16x^2-5x-236=0

Solution for 16x^2-5x-236=0 equation:

16x^2-5x-236=0

a = 16; b = -5; c = -236;
Δ = b2-4ac
Δ = -52-4·16·(-236)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-123}{2*16}=\frac{-118}{32}
=-3+11/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+123}{2*16}=\frac{128}{32}
=4
$